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authorLaurent Pinchart <laurent.pinchart@ideasonboard.com>2022-07-27 23:51:17 +0300
committerLaurent Pinchart <laurent.pinchart@ideasonboard.com>2022-07-28 14:54:41 +0300
commit48c106429a197d9c35c30523d3f5c711f3137333 (patch)
treed188e436875e54b1764eb79babdc7c2dc36f632c /LICENSES
parentf6d6181d3c91efa526b5027319331db9ac75f65b (diff)
libcamera: base: utils: Provide defopt to simplify std::optional::value_or() usage
The std::optional<T>::value_or(U &&default_value) function returns the contained value if available, or default_value if the std::optional has no value. If the desired default value is a default-constructed T, the obvious option is to call std::optional<T>::value_or(T{}). This approach has two drawbacks: - The \a default_value T{} is constructed even if the std::optional instance has a value, which impacts efficiency. - The T{} default constructor needs to be spelled out explicitly in the value_or() call, leading to long lines if the type is complex. Introduce a defopt variable that solves these issues by providing a value that can be passed to std::optional<T>::value_or() and get implicitly converted to a default-constructed T. Signed-off-by: Laurent Pinchart <laurent.pinchart@ideasonboard.com> Reviewed-by: Umang Jain <umang.jain@ideasonboard.com> Reviewed-by: Jacopo Mondi <jacopo@jmondi.org>
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